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Chapter 9 Matrices and Transformations 9MATRICES AND TRANSFORMATIONS Objectives After studying this chapter you should • be able to handle matrix (and vector) algebra with confidence, and understand the differences between this and scalar algebra; • be able to determine inverses of 2×2 matrices, recognising the conditions under which they do, or do not, exist; • be able to express plane transformations in algebraic and matrix form; • be able to recognise and use the standard matrix form for less straightforward transformations; • be able to use the properties of invariancy to help describe transformations; • appreciate the composition of simple transformations; • be able to derive the eigenvalues and eigenvectors of a given 2×2 matrix, and interpret their significance in relation to an associated plane transformation. 9.0 Introduction A matrix is a rectangular array of numbers. Each entry in the matrix is called an element. Matrices are classified by the number of rows and the number of columns that they have; a matrix A with m rows and n columns is an m×n (said 'm by n') matrix, and this is called the order of A. Example Given 142 A = , 3−10 then A has order 2×3 (rows first, columns second.) The elements of A can be denoted by a , being the element in the ith row and ij jth column of A. In the above case, a =1, a =0, etc. 11 23 235 Chapter 9 Matrices and Transformations Addition and subtraction of matrices is defined only for matrices of equal order; the sum (difference) of matrices A and B is the matrix obtained by adding (subtracting) the elements in corresponding positions of A and B. Thus 142 −123 A = and B = 3−10 43−3 065 22−1 ⇒ A +B= and A −B = . 72−3 −1−43 However, if 23 C = , 14 then C can neither be added to nor subtracted from either of A or B. If you think of matrices as stores of information, then the addition (or subtraction) of corresponding elements makes sense. Example A milkman delivers three varieties of milk Pasteurised (PA), Semi- skimmed (SS) and Skimmed (SK)) to four houses (E, F, G and H) over a two-week period. The number of pints of each type of milk delivered to each house in week 1 is given in matrix M, while N records similar information for week 2. PA SS SK PA SS SK E 843 E 478 F 12 0 3 F 10 0 5 =M =N 276 087 G G H 690 H 8100 Then 12 11 11 22 0 8 M +N = 21513 14 19 0 records the total numbers of pints of each type of milk delivered to each of the houses over the fortnight, 236 Chapter 9 Matrices and Transformations and −435 −202 N −M = −211 210 records the increase in delivery for each type of milk for each of the houses in the second week. Suppose now that we consider the 3×2 matrix, P, giving the prices of each type of milk, in pence, as charged by two dairy companies: 12 PA 35 36 SS 32 30=P SK 27 27 What are the possible weekly milk costs to each of the four households? Define the cost matrix as 12 cc E 11 12 c c F 21 22 = C c c G 31 32 c c H 41 42 Now c is the cost to household E if company 1 delivers the milk 11 (in the week for which the matrix M records the deliveries) and so c =8×35+4×32+3×27 11 =489p Essentially this is the first row of M 'times' the first 843 [] 35 column 32 of P. 27 Similarly, for example, c can be thought of as the 'product' of the 32 36 third row of M, 276 30 , with the second column of P, , so [] 27 237 Chapter 9 Matrices and Transformations that c =2×36+7×30+6×27 32 =444p This is the cost to household G if they get company 2 to deliver their milk. Matrix multiplication is defined in this way. You will see that multiplication of matrices X and Y is only possible if = the number of rows of Y the number of columns X Then, if X is an a×b matrix and B a c×d matrix, the () () product matrix XY exists if and only if b = c and XY is then an a×d matrix. Thus, for P = XY , () P= p , () ij where the entry p is the scalar product of the ith row of X ij (taken as a row vector) with the jth column of Y (taken as a column vector). Example Find AB when 25 142 A = , B = 20 3−10 −13 Solution A is a 2×3 matrix, B is a 3×2 matrix. Since the number of columns of A = the number of rows of B, the product matrix AB exists, and has order 2×2. p p P=AB = 11 12 p21 p22 2 p = 142 . 2=2+8−2=8 11 [] , etc −1 giving 811 P= 415 238
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