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File: Solved Problems Pdf 175037 | 5 Item Download 2023-01-28 03-45-04
chapter 5 legendre s equation 5 legendre polynomials legendre s differential equation is one of the most important odes in physics it arises in numerous problems particularly in boundary value ...

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                                               CHAPTER 5 
                                         Legendre’s Equation. 
                                                ( )
             5 Legendre Polynomials      
                                                
             Legendre’s differential equation 
                                      
                  (       )               (     )              ( )
                                                                           (           )  
             is one of the most important ODEs in physics. It arises in numerous problems, 
             particularly in boundary value problems for spheres .  The equation involves a 
             parameter n, whose value depends on the physical or engineering problem. So 
             (1) is actually a whole family of ODEs. For       we solved it in Example 3 of 
             Sec. 5.1 (look back at it). Any solution of (1) is called a Legendre function. 
             The study of these and other “higher” functions not occurring in calculus is 
             called the theory of special functions. Further special functions will occur in 
             the next sections. 
              Dividing (1) by       , we obtain the standard form needed in Theorem 1 
                                                     (   )
                                                                                    
                                      (       )     (       )
                                                        
                                                          (   )
                                                              
             and we see that the coefficients        and        of the new equation are 
                                              (    )     (    )
                                                             
             analytic at , so that we may apply the power series method. Substituting 
                                                
                                              ∑               ( ) 
                                                     
                                                 
                                                                       (      )
             and its derivatives into (1), and denoting the constant        simply by  , 
             we obtain 
                                                      1 
              
                      
                                                                                                                             
                                                                                                                                          
                           (    )∑ (   )                                            ∑                                 ∑        
                                                                                                                                     
                                                                                                                             
                     By writing the first expression as two separate series we have the equation 
                               
                                                               
                             ∑ (   )   
                               
                                                                                                                           
                                                                                                                                         
                                                  ∑ (   )     ∑       ∑        
                                                                                                                                    
                                                                                                                           
                     It may help you to write out the first few terms of each series explicitly, or you 
                     may continue as follows. To obtain the same general power    in all four 
                     series, set          (thus       ) in the first series and simply write 
                       instead of   in the other three series. This gives 
                      
                                                                                                                                   
                                                                                                                                                 
                      ∑(   )(   )                               ∑ (   )     ∑       ∑        
                                                                                                                                            
                                                                                                                                    
                      
                     (Note that in the first series the summation begins with     .) Since this 
                     equation with the right side 0 must be an identity in   if (2) is to be a solution 
                     of (1), the sum of the coefficients of each power of   on the left must be zero. 
                     Now occurs in the first and fourth series only, and gives [ remember that 
                         (   ) ] 
                                                                                                                             
                                                                                  
                                                                                                                         
                                                     
                                                    
                                                                   
                                                                                                                                                         
                                                                                                                
                                                                                                                                                     
                                                                                  
                                                                                                                                         
                                                                                                              
                                                                                                                                     
                                                                                                                                
                                                                                                   
                                                                                                                            
                                                                                       2 
                      
           
           
                                                (  )
                                                    
                              (   )                               
                                                      
                                                 
              occurs in the first, third, and fourth series and gives 
                                                    (   )
                        [    (   )]                            
                                                             
                                                      
             occurs in the first, third, and fourth series and gives 
                                        (   )     
                                                  
                                     (   )    
                                                
                                         
                                  (   )  (   )   
                                                    
                                              
                    The higher powers occur in all four series and give 
                 (   )(   )       [  (   )     (   )]     
                                                           
          The expression in the brackets can be written, as you may readily verify. 
          Solving (3a) for and (3b) for as well as (3c) for , we obtain the general formula 
          This is called a recurrence relation or recursion formula. It gives each 
          coefficient in terms of the second one preceding it, except for    and    , which 
                                                                
          are left as arbitrary constants. We find successively and so on. By inserting 
          these expressions for the coefficients into (2) we obtain (5) 
                                    where(6) 
                                                  (   )
                             (    )
                                                             
                                                            
                                                     
                                        (   )     
                                                  
                                     (   )    
                                                
                                         
                                       3 
           
                      
                                                                   (   )  (   )   
                                                                                                                  
                                                                                                     
                      
                                                                                
                                                (    )         (   )                  ( ) 
                                                                                   
                                                                       (            )
                     Divide Legendre function by                                       
                                                                                      (   )
                                                                                                                          
                                                             (           )           (           )
                                                                                         
                     Legendre function can be solved using a power series technique  
                                                              
                     Assume        ∑                        as a solution to Legendre function 
                                                     
                                              
                                                                                                                                          
                                       ∑                                  
                                               
                                           
                                                                                                                                            
                                   ∑                                                                                                            
                                                                                                                                      
                                            
                                             
                                                                                                                                           
                                    ∑                         (   )                                                                            
                                                                                                                                     
                                              
                     Substituting these  into Eq. (1)  we obtain 
                                   
                                                                                                                                            
                                 ∑[ (   )                             (   )             (   )    ] 
                                                                                                                                        
                                    
                                                                                                                             
                                                                                  
                                                                                                                         
                                                     
                                                    
                                                                   
                                                                                                                                                         
                                                                                                                
                                                                                                                                                     
                                                                                  
                                                                                                                                         
                                                                                                              
                                                                                                                                     
                                                                                                             
                                                                                                                     
                                                                                       4 
                      
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...Chapter legendre s equation polynomials differential is one of the most important odes in physics it arises numerous problems particularly boundary value for spheres involves a parameter n whose depends on physical or engineering problem so actually whole family we solved example sec look back at any solution called function study these and other higher functions not occurring calculus theory special further will occur next sections dividing by obtain standard form needed theorem see that coefficients new are analytic may apply power series method substituting its derivatives into denoting constant simply writing first expression as two separate have help you to write out few terms each explicitly continue follows same general all four set thus instead three this gives note summation begins with since right side must be an identity if sum left zero now occurs fourth only third powers give brackets can written readily verify solving b well c formula recurrence relation recursion coeffic...

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