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21. Chain rule Chain rule Statement 21.1. Statement Examples The power rule says that d n n−1 dx [x ] = nx . This rule is valid for any power n, but not for any base other than the simple input variable x. For instance, d 3 2 dx (2x+5) 6=3(2x+5) . 3 Table of Contents The function h(x) = (2x + 5) is built up of the two simpler functions g(x) = 2x + 5 and f(x) = x3: 3 3 h(x) = (2x+5) = (g(x)) = f(g(x)). ◭◭ ◮◮ Technically speaking, h is the composition of f and g. The next rule expresses the derivative of such a function in terms of the derivatives of its components. ◭ ◮ Chain rule. For functions f and g Page 1 of 8 d [f(g(x))] = f′(g(x)) · g′(x). dx Back Print Version In the composition f(g(x)), we call f the outside function and g the inside function. With this terminology, the rule says that the derivative of the composition of two functions is Home Page the derivative of the outside function evaluated at the inside function times the derivative of the inside function. 21.2. Examples Chain rule d Statement 21.2.1 Example Find the derivative (2x+5)3 . dx Examples 3 Solution Webegin by viewing (2x+5) as a composition of functions and identifying the outside function f and the inside function g. The outside function is the last thing you do when computing the expression for a given input x. Here, the outside function is the cubing function: 3 3 (2x+5) =f(g(x)), where f(x) = x and g(x)=2x+5. Next, we do the computations required for the chain rule formula: Table of Contents 3 f(x) = x g(x) = 2x+5 f′(x) = 3x2 g′(x) = 2 ◭◭ ◮◮ f′(g(x)) = 3(2x+5)2 ◭ ◮ Finally, we use the formula: d Page 2 of 8 dx [f(g(x))] = f′(g(x)) · g′(x) ↓ ↓ ↓ Back d 3 2 dx (2x+5) = 3(2x+5) · 2 Print Version Home Page d 5 21.2.2 Example Find the derivative dx sin(x ) . Solution Here, the outside function is the sine function: Chain rule sin(x5) = f(g(x)), where f(x) = sinx and g(x) = x5. Statement Examples So f(x) = sinx g(x) = x5 f′(x) = cosx g′(x) = 5x4 f′(g(x)) = cos(x5) giving d [f(g(x))] = f′(g(x)) · g′(x) dx Table of Contents d ↓ ↓ ↓ sin(x5) = cos(x5) · 5x4 ◭◭ ◮◮ dx ◭ ◮ d 5 21.2.3 Example Find the derivative sin x . dx Page 3 of 8 Solution Recalling that sin5 x means (sinx)5, we see that the outside function is the one that raises an input to the fifth power: Back 5 5 Print Version sin x = f(g(x)), where f(x) = x and g(x)=sinx. In order to reduce the number of steps, we go immediately to the chain rule formula and Home Page do the intermediate computations mentally as required: d [f(g(x))] = f′(g(x)) · g′(x) Chain rule dx d ↓ ↓ ↓ Statement sin5 x = 5(sinx)4 · cosx Examples dx d h 2 i 21.2.4 Example Find the derivative dx 5x −4x+3 . Solution Here, the outside function is the exponential function with base 5: x2−4x+3 x 2 Table of Contents 5 =f(g(x)), where f(x) = 5 and g(x)=x −4x+3. Trimming the number of steps a bit more, we omit the formula for the chain rule and ◭◭ ◮◮ just think “Derivative of outside function, evaluated at inside function, times derivative of inside function”: h i d 2 2 ◭ ◮ x −4x+3 x −4x+3 dx 5 =5 ln5·(2x−4). Page 4 of 8 d √ x 3 21.2.5 Example Find the derivative dx 5e +4x . Back Solution The outside function is the square root function: Print Version h i d p x 3 1 x 3 −1/2 x 2 dx 5e +4x = 2(5e +4x ) (5e +12x ). Home Page
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